H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Oooooo child i wish i could help
Answer:
add 17.50 to 8.75 you get 26.25
Answer:

Step-by-step explanation:

You will need to subtract if u are taking 15% off