Ask question

Ask question

All categories

3 years ago

6

The length of a rectangle is 1 units more than the width. The area of the rectangle is 56 units. What is the width, in units, of

the rectangle?

1 answer:

pishuonlain [190]3 years ago

8 0

Answer:

7

Step-by-step explanation:

$56=8*7\\8-7=1$ The width is smaller, so it is 7.

You might be interested in

Solve for x.<br><br> 2(x-4)=x + 4 <br><br> X=___

guapka [62]

2x-8=x+4
Get the x to the other side and the 8 to the opposite
2x-x=4+8
X=12

6 0

3 years ago

I need to solve it and what the answer right not wrong

marta [7]

Answer:

½

Step-by-step explanation:

There are 6 marbles. 3 are white.

So, it's 3/6 and that's ½

6 0

3 years ago

Pls help!!!!! i’m on a timer i’ll mark you brainliest!!!

kykrilka [37]

Answer:

-3.9

Step-by-step explanation:

4 0

3 years ago

What is the solution of the equation?<br> A. –5, 11<br> B. 5<br> C. 11<br> D. –11

rjkz [21]

Answer:

The solution is -5 or 11

Step-by-step explanation:

We are given the equation;

$4(3-x)^\frac{4}{3}-5=59$

We are supposed to solve the equation;

Taking 5 to the other side;

$4(3-x)^\frac{4}{3}=59+5$

$4(3-x)^\frac{4}{3}=64$

Dividing both sides by 4

$(3-x)^\frac{4}{3}=\frac{64}{4}$

$(3-x)^\frac{4}{3}=16$

We can cube both sides;

$((3-x)^\frac{4}{3})^3=16^3$

$(3-x)^4=4096$

Then we can get the fourth root on both sides of the equation;

$\sqrt[4]{ (3-x)^4} =\sqrt[4]{4096}$

We get;

$3-x=+8 or -8$

Solving for x

$3-x=8 and 3-x=-8$

Therefore;

$x=-5 or 11$

Therefore, the solution is -5 or 11

3 0

4 years ago

4+5(p-1) =34 solve it fast <br>

sashaice [31]

Answer:

P=7

Step-by-step explanation:

4+5(7-1) = 34

4 + 5(6) = 34

4+30=34

34=34

7 0

3 years ago