<span> tan(x)/ cos(x)-sec(x)
tanx/(cosx-1/cosx)
tanx/cos^2x-1)--------------------1-sin^2x=cos^2x
-tanx/sin^2x
-(sinx/cosx)/sin^2x
-1/sinxcosx
multiply 2/2
-2/2sinxcosx-------------sin2x=2sincosx
-2/sin2x------------------1/sinx=cosecx
-2cosec2x</span>
For this question, you would have to use the midpoint formula.
(X1 +X2 / 2 , Y1 + Y2 / 2)
In other words,
(9 + -3 / 2 , -7 +5 / 2)
(6 / 2 , -2 / 2)
(3 , -1)
Your midpoint is (3, -1)
Answer: y = 7x - 6
Step-by-step explanation:
7 = m (slope)
-6 = y-intercept
H(0)=8. You plug in zero for x you get y=8. So h(0)=8
Yeah there all right but I have a little hinch for the last and first one
