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nalin [4]
3 years ago
14

In a survey men in a certain country (ages 20-29), the mean height was 62.8 inches with a standard deviation of 2.8 inches, what

height represents the 99th percentile?
Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

the height that represents the 99th percentile is 69.324  inches

Step-by-step explanation:

Given that :

the mean height =  62.8 inches

standard deviation = 2.8  inches

For 99th percentile;

Let X be the random variable;

SO, P(Z≤ z)  = 0.99

From the standard normal z tables

P(Z )= 2.33

The standard z score formula is :

z = \dfrac{X- \mu}{\sigma}

2.33 = \dfrac{X- 62.8}{2.8}

2.33 × 2.8 = X - 62.8

6.524 = X - 62.8

6.524 +62.8 =  X

69.324  = X

X = 69.324

Therefore; the height that represents the 99th percentile is 69.324  inches

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?? Help with this question plz ‼️
baherus [9]

Answer:

The fastest runner is Katie

Step-by-step explanation:

In order to determine this, we must first put them all in the same terms. For the purpose of this, we will put them all in feet per second.

Katie

14 feet/1 second = 14 ft per second

Zach

576 feet/46 seconds = 12.52 ft per second

Tony

1 mile/533 seconds = 5280 feet/533 seconds = 9.91 ft per second

Will

827 feet/1 minute = 827 feet/60 seconds = 13.78 ft per second.

So we know that the fastest is Katie.

3 0
3 years ago
Find the area of the trapezoid.
ss7ja [257]

\bf \textit{area of a trapezoid}\\\\
A=\cfrac{h(a+b)}{2}~~
\begin{cases}
a,b=\stackrel{bases}{parallel~sides}\\
h=height\\[-0.5em]
\hrulefill\\
a=15.8\\
b=21.8\\
h=11.7
\end{cases}\implies A=\cfrac{11.7(15.8+21.8)}{2}
\\\\\\
A=\cfrac{11.7(37.6)}{2}\implies A=219.96

4 0
3 years ago
Read 2 more answers
for the school play adult tickets cost 4$ and children tickets cost 2$ natalie is working at the ticket counter and just sold 20
lilavasa [31]
Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be

4x + 2y = 20

There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.

When x=0,
4(0) + 2y = 20
y = 10

When x=1,
4(1) + 2y = 20
y = 8

When x=2,
4(2) + 2y = 20
y = 6

When x=3,
4(3) + 2y= 20
y = 4

When x = 4,
4(4) + 2y = 20
y = 2

When x = 5,
4(5) + 2y = 20
y = 0

When x = 6,
4(6) + 2y = 20
y = -2

A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:

   Number of adult tickets             Number of children tickets
                  0                                                   10
                  1                                                    8
                  2                                                    6
                  3                                                    4
                  4                                                    2
                  5                                                    0




6 0
3 years ago
Plzzzz help meeeeeee​
Amanda [17]

Answer:

34 jerseys

8 Social Media ads

$2,400 Spent on Radio ads

$360 per TV ad

Step-by-step explanation:

2856/84 = 34 jerseys

2000/250 = 8

200*12 = 2400

1800/5 = 360

If you know how many you have and how much they cost multiply

If you know how much was spent and how much they cost divide

If you know how much was spent and how many you have divide

8 0
3 years ago
Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag
VLD [36.1K]

Hey~freckledspots!\\----------------------

We~will~solve~for~i^{425}!

Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\

Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------

Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------

Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------

Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------

Answer:\\\large\boxed{-1+i}\\----------------------

Hope~This~Helped!~Good~Luck!

8 0
3 years ago
Read 2 more answers
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