The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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0.015 x 600 =9 so more than expected
Answer:
C
Step-by-step explanation:
∠ TUL + ∠ LUV = ∠ TUV , substitute values
x + 16 + 11x = 172 , that is
12x + 16 = 172 ( subtract 16 from both sides )
12x = 156 ( divide both sides by 12 )
x = 13 → C