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umka21 [38]
3 years ago
13

The student council wants to rent a chocolate fountain for an overnight dance-a-thon. Their budget allows them to spend a maximu

m of $250 on the chocolate fountain rental. A party rental store has a fountain available for $30 an hour after a deposit of $125. If x represents the number of hours, which inequality represents the situation?
Mathematics
2 answers:
Lilit [14]3 years ago
7 0

Answer:

its 3x+125 ≤ 250

Step-by-step explanation:

i got it right

vekshin13 years ago
6 0
$125 is a "must budget" so it will be the constant in the inequality

The fountain is $30 per hour. If they spend x hours, then their budget for fountain will be
fountain = 30x

The inequality
Their budget is maximum $250, that means they are able to spend less than or equal to $250
constant + fountain ≤ 250
125 + 30x ≤ 250
<em>This is the inequality expression</em>
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50% of the apartments in a certain building have windows and hardwood floors. 25% of the apartments without windows have hardwoo
alexdok [17]

Answer:E 83\frac{1}{3}

Step-by-step explanation:

50% of the apartment in a certain building have windows and hardwood floors.

25% of the remaining 50% apartment without window have hardwood floors.

40% of the apartment do not have hardwood floors i.e. 60 % have hardwood floor

Therefore percent of the apartments with windows have hardwood floors is

=\frac{50 percent of total\ apartment }{60\ percent\ of\ apartment}

=83\frac{1}{3}%

6 0
3 years ago
Which of the following statements is the only<br> sentence that is error-free?
Ray Of Light [21]
I don’t really know what the answer is
5 0
2 years ago
Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
Debora [2.8K]

So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

\int\limits^1_0 {x^{2} } \, dx = 13

We find

\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

4 0
2 years ago
I need help please and thank you​
Pani-rosa [81]
It equals 18.32 you can go to calculatorsoup.com and it shows you
8 0
3 years ago
Please help would greatly appreciate it
SCORPION-xisa [38]

Answer: 1. muiltply the two volumes 2. 273.32 cubic centimeters are your answers hopefully I'm correct on this.

3 0
3 years ago
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