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3 years ago

11

Which is the smallest decimal out of 2.473, 3.85, 2.72, 3.7, 3.15

2 answers:

Kobotan [32]3 years ago

8 0

Smallest decimal is 2.473

alina1380 [7]3 years ago

3 0

Answer:

The smallest decimal is 2.473

Step-by-step explanation:

3.85, 3.7, and 3.15 are larger than 2.72 and 2.473.

Now, it's 2.72 and 2.473. we can round 2.473 to make it 2.5 and 27.2 as 2.7. 2.473 is the smallest decimal.

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A gardener uses a coordinate grid to design a new garden. The gardener uses polygon WXYZ on the grid to represent the garden. Th

ValentinkaMS [17]

Answer:

A square

36 square yard.

Step-by-step explanation:

Given the following information:

W(3,3), X(-3,3), Y(-3,-3), and Z(3,-3)

So we need to graph those vertices and connect them in order.

(please have a look at the attached photo)

From the graph, it clear that the shape of the garden is a square.

Then, we need to calculate the length of the four sides

<u>Find the length of the side YZ. </u>

The length of side YZ = 3 + 3 = 6 yards because point Y and Z are on the same line y = -3 so we just need to find the distance between their x coordinate

<u>Find the length of the side WZ.</u>

The length of side WZ = 3 + 3 = 6 yards because point W and Z are on the same line x = 3 so we just need to find the distance between their y coordinate

=> the area of the square WXYZ:

= YZ*WZ

= 6*6

= 36 square yard.

7 0

3 years ago

Please help ASAP!!!!!

ra1l [238]

These tables have infinitely many values, but the simplest ones would be:
a) x|y
3|5
6|10
9|15

b) x|y
2|1
4|2
6|3

Your graph for c would look like the attached picture

7 0

3 years ago

Read 2 more answers

6/13 by 6/12? what is the answer

Leto [7]

(6/13)/(6/12)= (6/13)*(12/6)= 12/13
This rule for division applies to all fraction divisions

4 0

3 years ago

Read 2 more answers

let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0

1 year ago

Round off then estimate 18.9*5.2

Nataly [62]

18.9 rounded is 19
5.2 rounded is 5

19 * 5 = 95

7 0

3 years ago