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iren2701 [21]
3 years ago
12

How many times greater is the value if the digit 2 in 23876 than the value of the digit 2 in 3254

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0
In 23,876 the 2 represents 20,000 while in 3,254 the 2 represents 2,000. So, 2 is ten times greater in 23,876 than in 3,254 (20,000÷2,000=10).
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3 years ago
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Answer:

answer below:)

Step-by-step explanation:

Basically, start off by simplifying each pair of numbers.

The first one: 2^{2} x 5 = 4 x 5 = 20

The second one: 11^{1}= 11

The third: 8^{2}-60 = 64 - 60 = 4

Now from least to greatest, so that would be 4, 11, 20 or in this case it would then be 8^{2}-60,  11^{1},  2^{2} x 5

Hope it helped, good luck!!

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3 years ago
Find the measures of the angles of an isosceles triangle with a vertex angle of 42 degrees
I am Lyosha [343]

Answer:

69°, 69°, and 42°

Step-by-step explanation:

Isosceles triangles have three angles -- one vertex angle and two base angles.

The <u>base angles have the same measure</u> and the vertex angle has a different measure.

<u>Remember all triangles' interior angles sum to 180°.</u>

If the vertex angle is 42°, then the two base angles combined are:

180° - 42° = 138°

Since the base angles are the same, <u>each base angle is:</u>

138° ÷ 2 = 69°

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3 0
3 years ago
You estimate that there are 59 marbles in a jar. The actual amount is 47 marbles. Find the percent error. Round to the nearest t
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Answer:

25.5%

Step-by-step explanation:

% error = | estimate - actual | / actual × 100%

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4 0
4 years ago
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If x2+1/x2=18, find the value of x3−1/x3
Elden [556K]

Answer:

There are 2 answers : 76 or -76

Step-by-step explanation:

x^2+\dfrac{1}{x^2} =18\\\\(x-\dfrac{1}{x} )^2=x^2+\dfrac{1}{x^2} -2=18-2=16\\\\x-\dfrac{1}{x}=4\ or\ x-\dfrac{1}{x}-4\\\\(x-\dfrac{1}{x} )^3=x^3-\dfrac{1}{x^3} -3x^2*\dfrac{1}{x}+3x*\dfrac{1}{x^2}\\\\=x^3-\dfrac{1}{x^3}-3(x-\dfrac{1}{x})\\\\x^3-\dfrac{1}{x^3}=(x-\dfrac{1}{x} )^3+3(x-\dfrac{1}{x})\\\\if\ x-\dfrac{1}{x}=4\ then \ x^3-\dfrac{1}{x^3}=4^3+3*4=64-12=76\\\\if\ x-\dfrac{1}{x}=-4\ then \ x^3-\dfrac{1}{x^3}=(-4)^3+3*(-4)=-64-12=-76\\\\

7 0
3 years ago
Read 2 more answers
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