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xeze [42]
3 years ago
9

Three times a number decreased by 5 is at least 37. Which inequality represents this statement?

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

c

Step-by-step explanation:

Let the number be x

3x - 5

Atleast 37 means minimum 37

3x - 5 >=37

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What is the coordinate of the focus
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ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl
melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x}  \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

\frac{AQ}{QP}=\frac{AB}{CP}  \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19

\frac{BQ}{CQ}=\frac{AB}{CP}  \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

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3 years ago
Which of the following rational numbers is equivalent to a terminating decimal?
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A is the correct answer. When put into calculator, the decimals ends.
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Which of the following is the minimum value of the equation y = 2x2 + 5?
raketka [301]
(0, 5) is the minimum value.

Find the axis of symmetry by plugging the respective variables into -b/2a

-5/2(0) = 0

There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as

y = 2x^2 + 0x + 5

We plug 0 into f(x), establishing every x-value as 0.

f(0) = 2(0)^2 + 5
f(0) = 0 + 5
f(0) = 5

5 is now your vertex’s y-value. Plot the two values together.

(0, 5)

We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.
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