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hichkok12 [17]
4 years ago
8

How is 6 a solution for 2x^2+4x=3+3x^2

Mathematics
1 answer:
weqwewe [10]4 years ago
3 0
2x^2+4x-3-3X^2=0
simplify 2x^2+4x-3-3x^2 to -x^2+4x-3
-x^2+4x-3=0
Multiply both sides by -1
x^2-4x+3=0
Factor x^2-4x+3
1. Ask: Which two number add up to -4 and multiply to 3.
2. Answer:3 and -1.
3. Rewrite the expression as (x-3)(x-1):
(x-3)(x-1)=0
5Solve for x
1.Ask: when will (x-3)(x-1) equal zero.
2.Answer: when x-3=0 or x-1=0.
x=3,1
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irakobra [83]

Answer:

a) P(0, <u>2</u>), Q(<u>4</u>, 0)

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Step-by-step explanation:

The given equation for the line is 4·x + 2·y = 8

a) The coordinates of P = P(0, _)

Therefore, the point 'P', which is the point where the variable y = 0, is the point the (straight line) graph intercepts the x-axis (the x-intercept)

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With the help of MS Excel, the points P and Q are plotted in the attached graph

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Someone please help me with 6 and 7 and please show work
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