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IRINA_888 [86]
3 years ago
15

I need help vxbveud fhdhdbx

Mathematics
2 answers:
Zarrin [17]3 years ago
5 0

Step-by-step explanation:

What's the question? I cant help if there isnt a question.

AnnyKZ [126]3 years ago
3 0

Answer:

ishsushsishusbshsbshsb

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To solve the system of linear equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 by using the linear combination method, Henry d
seraphim [82]

Answer:

Step-by-step explanation:

Both lines have same slope so the graph of both equation will be same and hence it will overlap each other that is why the Henry  could only see one line.

Step-by-step explanation:

Given  : A system of linear equation 3x - 2y = 4 and 9x - 6y = 12  

We have to show whey when Henry  graphed the equations 3x-2y=4 and 9x-6y=12 he could only see one line.

Consider the given system of linear equation

3x - 2y = 4 ................(1)

9x - 6y = 12   ..................(2)

Since,

Equation (2) is multiple of equation (1),

3 × ( 3x - 2y = 4) = 9x - 6y = 12  

Also the slope of given equations are same

For equation (1),

Differentiate with respect to x, we get,

3-2dy/dx = 0

dy/dx = 3/2

Also for equation (2),

Differentiate with respect to x, we get,

9 - 6dy/dx = 0

dy/dx = 9/6 = 3/2

Since, both lines have same slope so the graph of both equation will be same and hence it will overlap each other.

That is why the Henry  could only see one line.

3 0
2 years ago
Find the standard form of the equation of the circle with endpoints of a diameter at the points (9,2) and (-7.4).
kicyunya [14]

Answer:

(x-1)²+(y-3)²=65

Step-by-step explanation:

the common view of the equation of a circle is:

a) (x-a)²+(y-b)²=r², where (a;b) - the centre of the required circle, r - the radius of the required circle;

b) using the coordinates of the endpoint of the given diameter it is possible to calculate the coordinates of the centre of the required circle and its radius²:

the coordinate x of the required circle is: (9-7)/2=1;

the coordinate y of the required circle is: (2+4)/2=3.

the radius² of the required circle is:

r²=0.25*[(9- -7)²+(2-4)²]=0.25*260=65.

c) after the substitution the values of 'a'; 'b' and 'r²' into the common equation of the circle:

(x-1)²+(y-3)²=65.

PS. additional: the given points (9;2) and (-7;4) belong to the final equation, if to substitute their coordinates into it.

The suggested way of solution is not the only one.

5 0
3 years ago
Find the equation of the line shown.<br> Pls help I’m so confused
Dahasolnce [82]

Answer:

the equation for a line is y=MX+b

m= slope(rise/run)

x=variable

b= y intercept

you would find the slope by looking at the rise over run which are both 1 and the line is negative so the slope would be negative one

you would find b by looking at where the y intercept is (y when x is zero) which is 9

y= -x+9

hope that helped

5 0
3 years ago
Please help that’s all i just need to make i’m correct it due tomorrow early so please
Aloiza [94]
The answer is 6 i think
5 0
3 years ago
The values of x and y vary directly
Rama09 [41]

Answer:

y = - \frac{3}{2} x

Step-by-step explanation:

Given that x and y vary directly then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = - 4, y = 6, thus

k = \frac{y}{x} = \frac{6}{-4} = - \frac{3}{2}

y = - \frac{3}{2} x ← equation of variation

7 0
3 years ago
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