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spin [16.1K]
3 years ago
6

How to find the rate of change over an interval when given a graph

Mathematics
1 answer:
inn [45]3 years ago
6 0

Answer:

(y2-y1)/(x2-x1)

Step-by-step explanation:

Using two coordinates, you can just plug in the corresponding (x,y) coordinates and you will get the slope, which is the rate of change over an interval

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Murljashka [212]

Answer:

b and a

Step-by-step explanation:

6 0
3 years ago
4x + 19 = ___+ 12
Anarel [89]

Answer:

-4x

Step-by-step explanation:

4x + 19 = -4x + 12

0 = 12 - 19

0 ≠ -7

4 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
Pl ease help what is with give brainlist answer!
expeople1 [14]

Answer:

option 1 is true. -1/2=-0.5

6 0
3 years ago
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What is the mean for the data set?
PIT_PIT [208]
83.3
Just add up all the numbers and divide by 6, as there are six numbers in this set of numbers
7 0
3 years ago
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