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3 years ago

What is the answer for 3÷4-1

Mathematics

2 answers:

Dmitry [639]3 years ago

6 0

-0.25 because when you divide 3 from 4 you get 0.75 so then subtract 1 from that and gets -0.25

umka2103 [35]3 years ago

5 0

Answer:

-1/4 OR -0.25

Step-by-step explanation:

Using PEMDAS:

3/4 = 3/4... or 0.75.

Subtracting 1: 3/4 - 4/4 (or 1) = -1/4. 0.75 - 1 = -0.25.

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Nookie1986 [14]

Answer:

12.5

Step-by-step explanation:

12x6 is 12 + 5 meters = 12.5m

3 0

2 years ago

HELP ME PLEASE

solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0

3 years ago

The graph of f(x)=3•2^x -3 is shown below. G(x) is a transformation of f(x). How would you write the equation for the function g

Bezzdna [24]

Answer:

Step-by-step explanation:

To find the appropriate equation, notice the red graph has shifted up about 6 units. This means that $3*2^x-3$ which is shifted by -3 will move 6 up. -3+6= 3. This means the function will have +3. Only B and C are options. Now test a point. Notice the red function crosses the y-axis at about 5 or 6 when x=0.