Question

A soccer ball is kicked at an angle of 30° to the horizontal with an initial velocity of 16 m/s. How high does the soccer ball go?
A. 9.8 m
B. 3.3 m
C. 0.6 m
D. 0.2 m

Answer 1

Vertical component of velocity = 16sin(30°) = 8m/s

at the highest point of flight, the velocity of the ball is 0 (that moment when it stops before starting to fall) so:
$v^2=u^2+2as$<u />
$0^2=8^2+(2\times-9.81\times s)$
$s= \frac{0^2-8^2}{2\times-9.81}$<u />
s=3.26m

So rounding up gives option B. (3.3m)