1. A fish swims 340 feet. Is this a distance or a displacement?

What happens to the gravitational force between two objects if:

kenny6666 [7]

Answer:

you can also get the best i have a problem with you have to be a good job for a while but it is a great way of doing it was really hard for the first one to have to be in the United

5 0

3 years ago

Two identical boxes (equal dimensions and mass) are at rest, the first on a 30-degree incline and the second on a 45-degree incl

klemol [59]

Answer:

A)

Explanation:

If both boxes are at rest, this means that the friction force must be equal to the component of the gravity force, trying to accelerate the box down the incline.

If the angle that the incline forms with the horizontal is θ, the component of the weight along the incline is as follows:

Fgp = m*g*sinθ

As sin θ is different for the 30-degree incline than for the 45-degree one, the components of the weight along the incline, that must be equal to the friction forces (due to the boxes are at rest), can't be equal each other, as masses are the same.

So, the frictional forces acting on the two boxes have NOT the same magnitude, so A) is FALSE.

All the other choices are true.

3 0

3 years ago

A 30 kg mass sits on a level surface with a coefficient of friction of .2. What net force is necessary to accelerate it

8_murik_8 [283]

Answer:

Explanation:

Idk

3 0

3 years ago

A 2.5 gram penny and a 1 gram paper clip are dropped from the Empire State Building.

frutty [35]

Answer:

According to Newton's second law of motion, the force $F$ exerted on an object is directly proportional to its mass $m$ and acceleration $a$ :

$F=m.a$ (1)

In the case of this two objects with different masses the force will be the weight $W$ , the force with which the objects are atracted to the Earth center due gavity $g$ :

$W=m.g$ (2)

This means we wil have two weights in this particular situation, where the weight of the penny is greater than the weight of the paper clip.

Nevertheless, we have another situation here:

When objects are dropped from a certain height and fall to the ground with the acceleration due gravity $g$ (in this case we are on Earth, so the gravity value is $9.8\frac{m}{s^{2}}$ ) is called free fall.

According to the experiments, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is the acceleration of gravity. This means these objects experience the acceleration of gravity regardless of their mass and therefore their weight.

For example, if we have two objects with different masses, the penny and the paper clip; where the first object is greater than the second; both will fall to the ground at the same time with the same gravity acceleration.

Now, in the real life we have air on Earth, and may have air resistance. In this case the greater object (the penny) will fall to the ground before the lesser object (the paper clip), because the paper clip was more affected by air resistance than the penny.

However, if the air resistance is too small that we can approximate it to zero in the calculations, in free fall the objects will accelerate downwards at $9.8\frac{m}{s^{2}}$ and hit the ground at approximately the same time.

7 0

4 years ago

If you put in 10 J of work to push 1 c of charge against and electric field what will be its voltage with respect to its startin

pashok25 [27]

It will have a value if 10V as a volt is a measurement of joules per charge so if there is 10j and 1c that makes 10V and since there is 10 J at its position using .5mv^2 we can solve this. First we find mass by knowing per electron it has a mass of 9.1E-31 kg and a charge is 1.6E-19C so we then divide 1C/1.6E-19 getting us roughly 6.2E18 electrons, then by multiplying the number of electrons by mass of an electron we get the total mass which is 5.642E-12kg. Now we can use the energy equation and plug in out mass so 10J=.5*(5.642E-12kg)*v^2. Then isolating v we end up with sqrt (2(10J)/5.642E-12kg)=V so V equals 3.5E12

3 0

3 years ago