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horsena [70]
3 years ago
11

I am lonely to death

Physics
2 answers:
serg [7]3 years ago
5 0
Rip wordddd ://///////
julia-pushkina [17]3 years ago
4 0

Answer:

sad

Explanation:

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Give two examples of spatial interference which can be easily observed.
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Answer : space and kite
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Un cuerpo suspendido en el aire es capaz de:
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Answer:

Explanation:

d

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Electromagnetic waves are sometimes demonstrated by rippling waves in water. However, electromagnetic waves are different from w
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The answer is D: all electromagnetic waves can travel in a vacuum
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Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through polystyrene. The waveleng
klemol [59]

Answer:

Speed:

2.01x10^{8}m/s

Wavelength:

4.24x10^{-7}m

Frequency:

4.74x10^{14}Hz

Explanation:

The speed of the laser as it travels through polystyrene can be determine by means of the equation of the refraction index:

n = \frac{c}{v} (1)

Where c is the speed of light and v is the speed of the laser in the medium.

Therefore, v will be isolated from equation 1

v = \frac{c}{n}

v = \frac{3x10^{8}m/s}{1.490}

v = 2.01x10^{8}m/s

Hence, the speed of the laser has a value of 2.01x10^{8}m/s

Frenquency:

Since, wavelength is the only one who depends on the media. Therefore the frequency in both medium will be the same.  

To determine the frequency it can be used the following equation

c = \nu \cdot \lambda  (2)

Where c is the speed of light, \nu is the frequency and \lambda is the wavelength

Then, \nu wil be isolated from equation 2.

\nu = \frac{c}{\lambda}  (3)

Before using equation 3 it is necessary to express \lamba in units of meters.

\lambda = 632.8nm . \frac{1m}{1x10^{9}nm} ⇒ 6.328x10^{-7}m

\nu = \frac{3x10^{8}m/s}{6.328x10^{-7}m}

\nu = 4.74x10^{14}s^{-1}

\nu = 4.74x10^{14}Hz

Hence, the frequency of the laser has a value of 4.74x10^{14}Hz

Wavelength:

To determine the wavelength it can be used:

v = \nu \cdot \lambda

\lambda = \frac{v}{\nu}

Where v is the speed of the laser through the polystyrene.

\lambda = \frac{2.01x10^{8}m/s}{4.74x10^{14}s^{-1}}

\lambda = 4.24x10^{-7}m

Hence, the wavelength of the laser has a value of 4.24x10^{-7}m

3 0
3 years ago
Elect the correct equations that show that when a 3.0-kg book is lifted 2.6 m its increase in gravitational potential energy is
grigory [225]
The increase in gravitational potential energy for an object of mass m is given by
\Delta U = mg \Delta h
where \Delta h is the increase in altitude of the object.

In our problem, m=3.0 kg, \Delta h= 2.6 m and g=10 m/s^2 (approximated value), so we have
\Delta U = mg\Delta h=(3.0 kg)(10 m/s^2)(2.6 m)=78 J
5 0
3 years ago
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