Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.
u = initial velocity = 30 : a = -g = 32 ft/sec^2
s(0) =initial height =4 ft.
We have the equation
where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration. Here final velocity is found out as follows
Substitute to get
Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.
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To reach 25 ft, put s = 25
and v must be atleast 0
Then we have
Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.
Answer:
42.5 meters per minute
Step-by-step explanation:
you divide 1700 by 40 to find the unit rate :)
Answer:
y=5
Step-by-step explanation:
First, write your current equation. Y=0x+b. Next, subsitute the x and y for the coordinates (2,5) to find the y-intercept. It should look like this: 5=0(2)+b. 2 times 0 equals 0, so you have 5=b, which means 5 is your y-intercept. Now, go back to the original equation Y=0x+b and replace the b with 5. However, since the slope is 0, that means it will be a horizontal line. So, you can just write it as y=5.
Answer:
1
Step-by-step explanation:
91: 7 13 11: 11 GCF:
The Greates Common Factor (GCF) is: 1
Well that's not really a real number...soooo.:)