Question

HELP PLEASEEEE

Answer 1

Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.

u = initial velocity = 30 :   a = -g = 32 ft/sec^2

s(0) =initial height  =4 ft.

We have the equation

where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration.  Here final velocity is found out as follows

Substitute to get

Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.

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To reach 25 ft, put s = 25

and v must be atleast 0

Then we have  

Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.