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OLEGan [10]
3 years ago
14

Solve the division problem -1 3/5 divided by -2/3 please help I already have 3 wrong and my brain feels pooped

Mathematics
2 answers:
wlad13 [49]3 years ago
5 0
The answer is 9/10

Hope this helps!
vaieri [72.5K]3 years ago
5 0

Answer:

EXACT FORM = 12/5  DECIMAL FORM=2.4  MIXED NUMBER FORM = 2   2/5

Step-by-step explanation:


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Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards
svet-max [94.6K]

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = (\text{Length+width})

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = \sqrt{\text{length}^{2}+\text{width}^{2}}

= \sqrt{(50)^{2}+(120)^{2}}

= \sqrt{2500+14400}

= \sqrt{16900}

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

7 0
3 years ago
-5.8c+4.2-3.1+1.4c combine like terms to create an equivalent expression
VMariaS [17]
-5.8c + 4.2 - 3.1 + 1.4c = -4.4c +1.1

Hope this helps! Ask me any questions if needed :)
4 0
3 years ago
Read 2 more answers
Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
2 years ago
What is the area of 4.5 and 5.5cm and 20cm
amm1812

Answer:

6.8

Step-by-step explanation:

8 0
3 years ago
Hassan invested $900 in an account that pays 4.75% interest compounded annually. Assuming no deposits or withdrawals are made, f
mestny [16]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$900\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year} \end{array}\dotfill &1\\ t=years\dotfill &9 \end{cases} \\\\\\ A=900\left(1+\frac{0.0475}{1}\right)^{1\cdot 9}\implies A=900(1.0475)^9\implies A\approx 1366.6

6 0
2 years ago
Read 2 more answers
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