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nikklg [1K]
4 years ago
5

3p + 13 = 37 Please help me solve (6 points)

Mathematics
2 answers:
Pani-rosa [81]4 years ago
6 0
3p + 13 = 37
- 13
3p = 24
÷ 3
p = 8

I hope this helps!
Firdavs [7]4 years ago
4 0
<span>3p + 13 = 37
Subtract 13 from both sides
3p=24
Divide 3 on both sides
Final Answer: p=8</span>
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PLEASE ANSWER QUICK!!! 30 POINTS
shusha [124]

Answer:

Solution given;

<ABD=<BAC+<ACB

<u>Since</u><u> </u><u>exterior</u><u> </u><u>angle</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>of</u><u> </u><u>two</u><u> </u><u>opposite</u><u> </u><u>interior</u><u> </u><u>angle</u>

26x+20=19x-15+9x+25

solve like terms

26x+20=28x+10

subtracting both by 10

26x+20-10=28x+10-10

Subtracting both side by 26x

10=28x-26x

2x=10

dividing both side by 2

2x/2=10/2

x=5

Now

<ABD=26*5+20=l50°

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4 0
3 years ago
Read 2 more answers
Help me solve this having trouble.
pishuonlain [190]
sin x= opposite / hypotenuse.
opposite=4
hypotenuse=5

sin x=4/5
x=arc sin (4/5)=53.13º

Answer: x=53.13º
7 0
4 years ago
W usng a calculator, paper and pencil, or mental math.
Paraphin [41]

Answer:

Mandy will take 67.5 mins to complete the 15 km race.

Step-by-step explanation:

Given:

Mandy runs 4 km in 18 min

She plans to run in a 15 km race.

We need to find how much time required to run 15 km.

4 km =18 min

15 km = time required for 15 km race

By Using Unitary method we get,

Time required for 15 km = \frac{18\times 15}{4}=67.5 mins

Hence time required by Mandy to complete 15 km race is 67.5 mins.

4 0
4 years ago
Help pls I will give you the brainiest I need the answers for all of them
gogolik [260]

the 1st one goes to 2 and the 2nd one goes to 3 the 3rd one goes to 1 the and so on

8 0
4 years ago
How do u find the scientific notation for this problem
dedylja [7]
You put both parentheses in standard form, then divide as if it were a normal problem. Once the quotient is found, move the decimal point to the right. Every time you move one space to the left, increase the exponent by one but also divide your quotient by 10
example:
10³/10²
1000/100
10
10=10^{1}
5 0
3 years ago
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