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patriot [66]
3 years ago
8

Please find the function rule and explain how you got it so it helps me understand better. I am SO bad with function rules. ;-;

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
The function rule for x is +1. When you want to get the next number in the set, you add one to the previous number. For example, -1 + 1 = 0.

The function rule for y is - 5. When you want to get the next number in the set, you subtract five to the previous number. For example, 9 - 5 = 4.

Hope this helps!
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Solve for x.<br><br> 2x+3y=20<br> -2x+y=4
Mama L [17]

Answer:

x = 1

Step-by-step explanation:

-2x + y = 4

y = 2x + 4

2x + 3y = 20

2x + 3(2x + 4) = 20

2x + 6x + 12 = 20

8x + 12 = 20

8x = 8

x = 1

3 0
2 years ago
the chumas family is driving from north carolina to california on vacation. They drive 330 in 5.5 hours How many hours would it
spin [16.1K]
An easy way is to work out their speed. Speed = distance/time.

First part: Speed = 330/5.5 = 60 mph

Finally, the second part:  time = distance / speed

So time = 720/60 = 12 hours
7 0
2 years ago
Read 2 more answers
Gianna skied three times farther than Xavier. Xavier skied 4 miles. How far did Gianna ski
lina2011 [118]
Gianna=3x
Xavier=x
since x=4, than multiply 4 by 3 and you get 12 miles.
Gianna skied 12 miles.

Hope this helped!! :D
3 0
3 years ago
Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants. 37 x2 − 6x
Dvinal [7]

Answer:

\dfrac{A}{x}+\dfrac{B}{x-6}

Step-by-step explanation:

Given the function \dfrac{37}{x(x-6)}, to write the form of its partial fraction on decomposition, we will separate the two functions separated by an addition sign. The numerator of each function will be constants A and b and the denominator will be the individual factors of each function at the denominator. The partial fraction of the rational function is as shown below.

= \dfrac{37}{x(x-6)}\\\\= \dfrac{A}{x}+\dfrac{B}{x-6}

<em>Since we are not to solve for the constants, hence the partial fraction is </em>\dfrac{A}{x}+\dfrac{B}{x-6}

8 0
3 years ago
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
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