Answer:
This is a many-to-one function as the value of y = -1 corresponds to two values of x:
Step-by-step explanation:
<u>Function</u>
A special relationship where each input (x-value) has a single output (y-value).
A function is <u>one-to-one</u> if each value in the range (y-values) corresponds to exactly one value in the domain (x-values).
A function is <u>many-to-one</u> if some values in the range (y-values) correspond to more than one (many) value in the domain (x-values).
This is a many-to-one function as the value of y = -1 corresponds to two values of x:
This is not a function as the value of x = -5 corresponds to two values of y:
This is not a function as the value of x = -2 corresponds to two values of y:
This is not a function as the value of x = -4 corresponds to two values of y:
Answer:
49 pi
Step-by-step explanation:
I'll assume you want to know how big the carpet is. You need to find the area of the room, which is a circle. The area of a circle is given as pi*r^2, where r is the radius. The diameter is twice the radius, so as the problem gives us a diameter of 14, the radius would be 7. Plug in 7 for r, and we get 49pi.
Answer:
(a) 25
(b) 9.27
Step-by-step explanation:
Step 1
We have to rearrange the given days set from least to highest
35, 40, 45, 55, 60
(a) the range
Range = The highest number - The least number
= 60 - 35
= 25
(b) the standard deviation of the data set
35, 40, 45, 55, 60.
We find the Mean
Mean = Sum of values/Number of values
= 35+40+45+55+60/5
= 235/5
= 47
We can find the standard deviation now.
The formula =
√(x - Mean)²/n
= √(35 - 47)²+ (40 + 47)² + (45 - 47)² + (55 - 47)² + (60 - 47)²/5
= √144 + 49 + 4 + 64 +169/5
= √430/5
= √86
= 9.273618495
Approximately = 9.27
Answer:
The answer to the question is
It take for the golf ball hit on Mars to reach the ground 8.284 s longer.
Step-by-step explanation:
To Solve the question, we note that the equation of motion is given to us as
h = -1.9·t² + 26·t
Therefore the height
We compare the above equation with the equation of of motion
S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and - 0.5×g = -1.9
Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²
We now have the time taken to maximum height given by
v = u - g·t where v = 0 at maximum height
We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds
The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s
The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.
Answer:
The bearing needed to navigate from island B to island C is approximately 38.213º.
Step-by-step explanation:
The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:
(1)
Where:
- The distance from A to C, measured in miles.
- The distance from A to B, measured in miles.
- The distance from B to C, measured in miles.
- Bearing from island B to island C, measured in sexagesimal degrees.
Then, we clear the bearing angle within the equation:
(2)
If we know that 
, 
, 
, then the bearing from island B to island C:
![\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%287%5Cmi%29%5E%7B2%7D%2B%288%5C%2Cmi%29%5E%7B2%7D-%285%5C%2Cmi%29%5E%7B2%7D%7D%7B2%5Ccdot%20%288%5C%2Cmi%29%5Ccdot%20%287%5C%2Cmi%29%7D%20%5Cright%5D)
The bearing needed to navigate from island B to island C is approximately 38.213º.
