What about it? What is the question?
Answer: 1/67600
Step-by-step explanation:
probability that the code is 43MZ:
Probability = (Total Required outcome / total possible outcomes)
Possible outcomes (digit) = (00,.............. ..., 99)
2.) possible outcomes (alphabet) = (A, B,............... .., Z)
P(43MZ) = P(43) × P(M) × P(Z)
P(43) = 1/100
P(M) = 1/26
P(Z) = 1/26
THEREFORE ;
P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600
From the graph we can see that in the interval [0,1] the value of y is less than 1.
In the interval [1,2] the value of y value is 2 to 4.
In the interval [2,infinity) the graph is going up, and the value of y is greater than or equal to 4.
Therefore, the graph going up after y=4 above the line.
Therefore, the minimum y-value is 4 after which the exponential function will always be greater than the linear function.
0.65 =
6/10 = 0.6
+
5/100 = 0.05.
Add: 0.6 + 0.05 = 0.65.
Hope this helped☺☺