Complete the proof of ∆JKL ≅ ∆LMN, by providing the reason for each of the statements below. Reasons MAY be used more than once.
NOT ALL reasons will be used.
1. JK ∥ LM, KL ∥ MN (Given)
2. ∠KJL ≅ ∠MLN; ∠KLJ ≅ ∠MNL
a. Reflexive Property
b. Alternate Interior Angles
c. Corresponding Angles
d. ASA
e. AAS
3. JK ≅ LM (Given)
4. ∆JKL ≅ ∆LMN
a. Reflexive Property
b. Alternate Interior Angles
c. Corresponding Angles
d. ASA
e. AAS
1. JK ∥ LM, KL ∥ MN (Given)
2. ∠KJL ≅ ∠MLN; ∠KLJ ≅ ∠MNL
a. Reflexive Property
b. Alternate Interior Angles
c. Corresponding Angles
d. ASA
e. AAS
3. JK ≅ LM (Given)
4. ∆JKL ≅ ∆LMN
a. Reflexive Property
b. Alternate Interior Angles
c. Corresponding Angles
d. ASA
e. AAS
1 answer:
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Answer:
1=30
2=90
3=21
4=39
5=39
6=24
7=24
8=66
9=66
10=21
11=60
12=120
13=60
14=120
15=48
16=105
17=27
18=129
19=51
20=129
21=51
Step-by-step explanation:
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Answer:
So, the correct option is A. x = 9, y = 14 , Sides are 11 and 20
Step-by-step explanation:
P.S - the exact question is -
As given in the question ,
Side AB = Side AD
⇒y - 3 = x + 2
⇒y - x = 2 + 3 = 5
⇒y - x = 5 .........(1)
Also, given
Side BC = Side CD
⇒2x + 2 = x + 11
⇒2x - x = 11 - 2
⇒x = 9
∴ equation (1) becomes
y - 9 = 5
⇒y = 5 + 9 = 14
⇒y = 14
∴ we get
x = 9, y = 14
Now,
as given ,
Side AB = y - 3
⇒ AB = 14 - 3 = 11
Side BC = 2x + 2
⇒ BC = 2(9) + 2 = 18 + 2 = 20
Side CD = x + 11
⇒ CD = 9 + 11 = 20
Side DA = x + 2
⇒DA = 9 + 2 = 11
∴ we get
The sides are 11 and 20
So,
The correct option is A. x = 9, y = 14 , Sides are 11 and 20
