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Bas_tet [7]
3 years ago
5

The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in ast

ronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?
Mathematics
2 answers:
arlik [135]3 years ago
7 0

Answer:

D 2^3/2

you welcome

Oxana [17]3 years ago
6 0

Answer:

The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?

Step-by-step explanation:

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Arada [10]
Answer is 283
283 x 0.35 = 99.1

3 0
3 years ago
Please help with this question
aleksandr82 [10.1K]

Answer:

D) -9/4

Step-by-step explanation:

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5 0
3 years ago
Mark studied a group of 30 whales. If each will wait approximately 3.8×10 to the fifth power, pounds find the total weight of al
natta225 [31]

Answer:

11.4 x 10 ^ 6

Step-by-step explanation:

  1. First, you have to convert 3.8 x 10^5 out of scientific notation. To do that, multiply 3.8 * 10^5, you'll get 380,000. This is the weight of each whale.
  2. Now multiply the weight of each whale times 30. 380,000 * 30 = 11,400,000
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7 0
3 years ago
Rhombus ADEF is inscribed in △ABC such that the vertices D, E, and F lie on the sides AB , BC , and AC respectively. Find the si
Oksanka [162]
<h3>Answer:</h3>

3 11/15 cm

<h3>Step-by-step explanation:</h3>

AE is the angle bisector of ∠A, so divides the sides of the triangle into a proportion:

... BE:CE = BA:CA = 7:8

Then ...

... BE:BC = 7 : (7+8) = 7:15

ΔDBE ~ ΔABC, so DE = 7/15 × AC

... DE = 7/15 × 8 cm = (56/15) cm

... DE = 3 11/15 cm

3 0
3 years ago
Helpppppppp ion know how to do this
mr_godi [17]

Answer:

x = 34

Step-by-step explanation:

100 + 12 + x = 180

112 + x = 180

68/2 = 34

X = 34

Have an amazing day!

Please mark brainliest!

7 0
2 years ago
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