The system of Roman numerals is based on using special symbols to denote decimal digits I=1, X=10, C=100, M=1000, and their halves V=5, L=50, D=500. Positive integers are written by repeating these numerals.
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The solution is B = 43
Step-by-step explanation:
Simplify and solve for the unknown for 5(B + 3) = 4(B - 7) + 2B
- Simplify each side
- Add the like terms in each side if need
- Separate the unknown in one side and the numerical term in the other side to find the value of the unknown
∵ 5(B + 3) = 4(B - 7) + 2B
- Multiply the bracket (B + 3) by 5 in the left hand side and multiply
the bracket (B - 7) by 4 in the right hand side
∵ 5(B + 3 ) = 5(B) + 5(3) = 5B + 15
∵ 4(B - 7) = 4(B) - 4(7) = 4B - 28
∴ 5B + 15 = 4B - 28 + 2B
- Add the like terms in the right hand side
∵ 4B + 2B = 6B
∴ 5B + 15 = 6B - 28
- Add 28 to both sides
∴ 5B + 43 = 6B
- Subtract 5B from both sides
∴ 43 = B
- Switch the two sides
∴ B = 43
To check the answer substitute the value of B in each side if the two sides are equal then the solution is right
The left hand side
∵ 5(43 + 3) = 5(46) = 230
The right hand side
∵ 4(43 - 7) + 2(43) = 4(36) + 86 = 144 + 86 = 230
∴ L.H.S = R.H.S
∴ The solution B = 43 is right
The solution is B = 43
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Y= -1 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
600 m³
Step-by-step explanation:
Given:
- length of swimming pool = 30 m
- width of swimming pool = 10 m
- depth at deep end = 3 m
- depth at shallow end = 1 m
To find the volume of the water in the pool, find the area of a cross section (see attached image) and multiply it by the width of the pool.
<u>Area of cross section</u>
= area of rectangle - area of triangle
= (3 × 30) - [1/2 × 30 × (3 - 1)]
= 90 - 30
= 60 m²
<u>Volume of pool</u>
= area of cross section × width
= 60 × 10
= 600 m³