Answer:
what i did was multiply 33*6 and got 198 and then 228-198 to find out that the initial fee was 30 dollars. then multiply 33*9+30 to get a 9-month total cost of $327
Step-by-step explanation:
cost = $33 per month + fee
1. c(m) = 33m + f
33(6) + f = 228
198 + f = 228
f = $30 membership fee
c(m) = 33m + 30
2. at 9 months: 33(9) + 30 = $327
hopefully this helps :)
have a nice day !!
The answer is a = 0, b = -5, and c= 39.
<u>Step-by-step explanation</u>:
<u>step 1</u> :
A quadratic equation means that it should have at least one squared term.
<u>step 2</u> :
The standard form is ax² + bx + c = 0.
<u>step 3</u> :
The solution to the quadratic equation is usually written in the form
x = (-b ± √(b2 − 4ac))/(2a)
where a = coefficient of x^2
b = coefficient of x
c = constant term
<u>step 4</u> :
The given equation is -5x +32.
∴ The answer is a = coefficient of x^2 = 0
b = coefficient of x = -5
c = constant term = 39
Answer:
8 is the probablitiy
Step-by-step explanation:
4+5=9 -1 = 8
Answer:
she took 13 classes that were worth 3 credits
Step-by-step explanation:
well we know that some of the classes are worth 3 and some are worth 4 and that all of these together = 59 so your first equation would be
3x+4y=59
x would be the number of classes worth 3 credits and y would be the number of classes worth 4 credits.
then it says the total number of classes that they took was 18 so we know that
x + y =18.
you want to solve for the number of 3 credit classes so lets go ahead and get rid of the y values. SO you need you multiply the x+y equation by 4
4x+4y=72
then subtract 4x+4y=72 from 3x+4y=59 to get
-x = -13
and then x is a negative so you need to divide -1 from both sides and you get that she took 13 classes that were worth 3 credits.