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2 years ago

Help for question 7 please

Mathematics

2 answers:

Gelneren [198K]2 years ago

8 0

Remember that i² = -1. Your expression can be rewritten as
-3×*(i²)² +2i×(i²) +2×(i²) +√(9×(i²))
= -3×(-1)² +2i×(-1) +2×(-1) +√((3i)²)
= -3 -2i -2 +3i
= -5 +i . . . . . . . . . . . . matches the 1st selection

scoray [572]2 years ago

7 0

◆ COMPLEX NUMBERS ◆

$given \: expression \: is \: - \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{ - 9} \\ \\ we \: know \: that \: , \: \\ i = \sqrt{ - 1} \\ \\ {i}^{2} = - 1 \\ \\ {i}^{3 } = - i \\ \\ {i}^{4} = 1 \\ \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{9} i \\ = - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + 3i \\ \\ using \: the \: above \: properties \: of \: iota \: (i) \\ \\ = - 3(1) + 2( - i) + 2( - 1) + 3i \\ \\ = - 3 - 2i - 2 + 3i \\ \\ = (- 5 + i) \: \: \: ans.$

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30 Points! please help!

SVEN [57.7K]

Answer:

18) 4 * 10 ^ -10

19) t ^ 9

Step-by-step explanation:

18. When multiplying in scientific notation, just multiply the regular numbers together and add the exponents for the tens.

So it'll be 40 * 10^-11

However, the beginning number should have the decimal right after the 4, not any place after (for example, it's 3.056, not 30.56 or 3056.)

To fix this, move the decimal place forward one space from 40. to 4.0, and add 1 to the -11 power.

So the answer is now 4 * 10^-10

19. When dividing exponents, if the base number is the same, you can divide. (Basically, you can not divide x^2 and y^3 because x and y aren't the same)

Since in this case it's t, you can divide.

Dividing exponents is simple: just subtract them.

14 - 5 = 9

so the answer is t ^ 9

3 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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irakobra [83]

Answer:

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Step-by-step explanation:

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kramer

Answer: 9

Step-by-step explanation:

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3 years ago

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