What is the sine of C if triangle ABC has b = 3, c = 7, and angle B = 15°?
2 answers:
Answer:
sin C = 0.6039111053
Step-by-step explanation:
The Law of sine can be used to solve this question. Sine formula for triangle can be represented using the picture of the triangle above.
a/sin A = b/sin B = c/sin C
b = 3
c = 7
B = 15°
Inputting the value in the equation
b/sin B = c/sin C
3/sin 15 = 7/sin C
cross multiply
3 sin C = 7 sin 15°
3 sin C = 7 × 0.2588190451
3 sin C = 1.811733316
sin C = 1.811733316/3
sin C = 0.6039111053
You might be interested in
Simple...
3*10=5*6
2*8=4*4
21+11=9+23
23+20=2+41
30-5=40-15
90-80=20-10
Thus, your answers.
3*10=5*6
2*8=4*4
21+11=9+23
23+20=2+41
30-5=40-15
90-80=20-10
Thus, your answers.