What is the sine of C if triangle ABC has b = 3, c = 7, and angle B = 15°?
2 answers:
Answer:
sin C = 0.6039111053
Step-by-step explanation:
The Law of sine can be used to solve this question. Sine formula for triangle can be represented using the picture of the triangle above.
a/sin A = b/sin B = c/sin C
b = 3
c = 7
B = 15°
Inputting the value in the equation
b/sin B = c/sin C
3/sin 15 = 7/sin C
cross multiply
3 sin C = 7 sin 15°
3 sin C = 7 × 0.2588190451
3 sin C = 1.811733316
sin C = 1.811733316/3
sin C = 0.6039111053
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Answer:
When using the given information, the diameter of the circle is going to be 28 mL.
Step-by-step explanation:
First, we need to know the formula for finding the area of a circle.
Now, we need to rearrange the formula so we can find the radius.
Next, we plug in the given area into the equation.
Now that we have the radius, we can find the diameter. The radius is half the length of the diameter. So, in order to find the diameter, we have to multiply the radius by 2.
So, the diameter of the circle is 28 mL