What is the sine of C if triangle ABC has b = 3, c = 7, and angle B = 15°?

Mathematics

2 answers:

MatroZZZ [7]3 years ago

7 0

0.6039 is the answer. please give me brainiest.

bekas [8.4K]3 years ago

3 0

Answer:

sin C = 0.6039111053

Step-by-step explanation:

The Law of sine can be used to solve this question. Sine formula for triangle can be represented using the picture of the triangle above.

a/sin A = b/sin B = c/sin C

b = 3

c = 7

B = 15°

Inputting the value in the equation

b/sin B = c/sin C

3/sin 15 = 7/sin C

cross multiply

3 sin C = 7 sin 15°

3 sin C = 7 × 0.2588190451

3 sin C = 1.811733316

sin C = 1.811733316/3

sin C = 0.6039111053

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