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matrenka [14]
3 years ago
11

Robbie had p coins. Then he found 59 more coins in a drawer. Choose the expression that shows how many coins Robbie has now.

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

y=p+59

Step-by-step explanation:

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Solve the quadratic equation 3x^2+x-5=0
irinina [24]
-1 <span>± </span><span><span>√61 / 6. Negative 1, plus or minus square root of 61 divide by 6</span></span>
5 0
3 years ago
In an agricultural class, there are 17 freshmen students and 19 sophomore students. What ratio compares the number of freshmen t
zheka24 [161]

Answer:

  B. F:S = 17 to 19; S:F = 19 to 17

Step-by-step explanation:

Put the corresponding numbers in the corresponding parts of the ratio you want to write:

  freshmen to sophomores (F:S)

  17 to 19

___

  sophomores to freshmen (S:F)

  19 to 17

These pairs of numbers match choice B.

5 0
3 years ago
Angeline would like to make 8 identical bowls for a gift to her family. Each bowl required 3/4 lbs. of clay. The clay is sold in
lana66690 [7]

Answer:

2

Step-by-step explanation:

8 × .75 = 6lbs

she'd need 6lbs so she'd buy two bags of 5lbs

8 0
3 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
3 years ago
What is the area of a garden that measures 4mx4mx6mx4mx10mx8m
topjm [15]

The area of the garden is 120 square metre

<h2>Explanation:</h2>

The picture of the garden is shown below. In this problem, we have:

  • One square
  • Two rectangles

Recall that the area of a square is given by:

A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square

On the other hand, the area of a rectangle is given by:

A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle

Therefore:

FOR THE SQUARE:

L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}

FOR THE RECTANGLE 1:

L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}

FOR THE RECTANGLE 2:

L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}

Finally, the area of a garden is the sum of the three areas:

A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}

<h2>Learn more:</h2>

Area of a pizza: brainly.com/question/12878495

#LearnWithBrainly

4 0
3 years ago
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