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Karo-lina-s [1.5K]
3 years ago
9

PLS HELP!!look at image!!

Mathematics
1 answer:
Katarina [22]3 years ago
5 0

9514 1404 393

Answer:

  C.  D"(0, -1)

Step-by-step explanation:

The attachment shows the two transformations. The original figure is in quadrant III, so rotating it 270° CCW will put the first image in quadrant II. Translating it down and right will move most of it to quadrant IV.

As you can see in the attachment, the location of D" is now (0, -1).

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Carlos needs 1.7 meters of wire for one project and 0.8 meters of wire for another project shade the model to represent the tota
vesna_86 [32]

Answer:

Step-by-step explanation:

Given that ;

Carlos needs 1.7 meters of wire for one project    &

0.8 meters of wire for another project

we are to shade the model to represent the total amount of wire Carlos needs .

NOW;

For both projects ; Carlos needs ( 1.7 + 0.8) meters of wire =  2.5 meters of wire

In  the  attached files below. the first picture shows the diagram attached to the question and the second one shows the shading of the model which represent the total amount of wire Carlos needs.

7 0
3 years ago
Which side lengths form a right triangle?
vampirchik [111]

Answer:

A and C

Step-by-step explanation:

<h3>A</h3>

=  \sqrt{ {5}^{2} + ( \sqrt{6})^{2}  }  \\  =  \sqrt{25 + 6}  \\  =  \sqrt{31}

<h3>C</h3>

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5 0
3 years ago
Read 2 more answers
Will you please help me
PtichkaEL [24]

Answer:

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Step-by-step explanation:

4 0
3 years ago
What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25
elixir [45]

Answer:

y =  \frac{5}{4} x - 1

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First rewrite the equation of the given line in the form of y=mx +c.

4x+5y=25

5y= -4x +25

y =  -  \frac{4}{5} x + 5

The gradient of the given line is -  \frac{4}{5}

The product of the gradient of perpendicular lines is -1.

( -  \frac{4}{5} )(gradient \: of \: line) =  - 1 \\ gradient \: of \: line =  - 1  \div ( -  \frac{4}{5} ) \\ gradient \: of \: line =  \frac{5}{4}

Thus, m= \frac{5}{4}

y =  \frac{5}{4} x + c

Substitute a coordinate to find c.

When x= -4, y= -6,

- 6 =  \frac{5}{4} ( - 4) + c \\  - 6 =  - 5 + c \\ c = 5 - 6 \\ c =  - 1

Hence, the equation of the line is

y =  \frac{5}{4} x - 1

7 0
3 years ago
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3 years ago
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