7x (13x^2 - 8) = 91x^3 - 56x
68>6t+4 when ever the number is per something(the 6) you put the variable with it and 4 is the constant
t>16
The are is eleven because 2×11= 22
To solve for <em>x</em>, we must first isolate the term containing <em>x</em> which in this problem is 5x.
Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.
On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.
Now we can finish things off by just dividing both sides of the equation by 5. On the left the 5's cancel and on the right, 10 divided by 5 is 2 so <em>x = 2</em>.