Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
X = k/p^3
125 = k/10^3 = k/1000
1000 x 125 = k
k = 125000
x = 125000/p^3
The profit is given by G = px - (125 + 2x) = p(125000/p^3) - 125 - 2(125000/p^3) = 125000/p^2 - 250000/p^3 - 125
For maximum profit:
dG/dp = 0
dG/dp = -250000/p^3 + 750000/p^4 = 0
750000 - 250000p = 0
p = 750000/250000 = 3
Therefore the price that will yeaild maximum profit is $3.
Sent you a pic of the product of the expressions.
Hi!
The answer is 9749821.
I did 9809821 - 6000.
I hope this answer helps!
I would love it if you helped me with my question too!