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Mrrafil [7]
3 years ago
8

Ronald is 26 years old and starting an IRA (individual retirement account). He is going to invest $200 at the beginning of each

month. The account is expected to earn 2.75% interest, compounded monthly.How much money will Ricky have in his IRA when he retires, at age 65? $434,065.20 $167,868.30 $86,350.79 $14,053.63
Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

The formula for the future value A, given annual interest rate r, number of years t, and deposit amount P can be written as

... A = P(1 +r/12)((1+r/12)^(12t) -1)/(r/12)

Filling in the given numbers, you have

... A = 200(1+.0275/12)((1+.0275/12)^(12·39) -1)/(.0275/12) ≈ 167,868.30

The appropriate choice is $167,868.30.

_____

The formula is the one for the sum of a geometric series. It can be useful to consider the last deposit made as the first term of the series.

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Anyone have the answer for this
sergiy2304 [10]

\huge\bold{Given:}

Length of the base = 16 km.

Length of the hypotenuse = 34 km. \huge\bold{To\:find:}

✎ The length of the missing leg ''a".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

The length of the missing leg "a" is\boxed{30\:km}.

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

Using Pythagoras theorem, we have

({perpendicular})^{2}  +  ({base})^{2}  =  ({hypotenuse})^{2}  \\ ⇢ {a}^{2}  +  ({16 \: km})^{2}  =  ({34 \: km})^{2}  \\ ⇢ {a}^{2}   + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 1156 \:  {km}^{2}  - 256 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 900 \:  {km}^{2}  \\ ⇢a \:  =  \sqrt{900  \: {km}^{2} }  \\ ⇢a =  \sqrt{30 \times 30 \:  {km}^{2} }  \\ ⇢a = 30 \: km

\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}

\huge\bold{To\:verify :}

( {30 \: km})^{2}  +  ({16 \: km})^{2}  =(  {34 \: km})^{2}  \\ ⇝900 \:  {km}^{2}  + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\⇝1156 \:  {km}^{2}  = 1156 \:  {km}^{2}   \\ ⇝L.H.S.=R. H. S

Hence verified. ✔

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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