How do you solve (8^1)^0
1 answer:
Answer:
1
Step-by-step explanation:
When numbers are raised to an exponent/power, it means how many times you are multiplying the number by itself.
Follow BEDMAS order. (Brackets, exponents, division/multiplication, addition/subtraction).
Solve inside the brackets of (8^1)^0 first
(8^1)^0 8^1 is 8. (Any number ^1 is itself).
= 8^0 Any number to the power of 0 is 1.
= 1
You can also follow the exponent rule where:
(8^1)^0 = 8^(1*0) = 8^0 = 1
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Answer:
Option (a) is correct.
Step-by-step explanation:
Given : equation 2x + 3y ≤ 6
We have to choose out of given option the graph that shows the graph of the solution set of 2x + 3y ≤ 6
Consider the given equation 2x + 3y ≤ 6
We first find the points where the equation cut x- axis and y-axis.
Thus,
For x - axis put y = 0 ,
We get 2x + 3(0) ≤ 6 ⇒ 2x ≤ 6 ⇒ x ≤ 3
Thus, point (3,0)
For y - axis put x = 0 ,
We get 2(0) + 3y ≤ 6 ⇒ 3y ≤ 6 ⇒ y ≤ 2
Thus, point (0,2)
For region we choose a test point and find the value of x and y on that test point and check whether it satisfy the inequality satisfies or not.
Consider the point (0, 0) , then inequality becomes,
2(0) + 3(0) ≤ 6 ⇒ 0 ≤ 6 (true)
Hence, region below the line will be considered.
Thus, Option (a) is correct.
