Answer:
? = 109 degrees
Step-by-step explanation:
45 + 75 + _ = 180 ( look for vertical angles)
45 + 75 + 60 = 180
60 +79 + _ = 180 (look for a straight line that forms 180 degrees)
60 + 79 + 41 = 180
68 + 41 + _ = 180 (look for a triangle that adds up to 180)
68 + 41 + 71 =180
180 - 71 = 109 (look for a linear pair)
Answer:
I believe A is the answer
Answer:
I got a fraction but, H= 7/4
Answer:
The function of height has a maximum value.
Step-by-step explanation:
Maximum or Minimum:
A given function f(x).
- Find out f'(x) and f''(x)
- Then set f'(x)=0 which gives x=a.
- f''(a) > 0 , then at x=a , f(x) has minimum value.
- If f''(a)<0 , then at x=a, f(x) has maximum value.
Given that, a baseball is thrown with with an velocity of 32 feet per second.
The equation of height is

Differentiating with respect to t

Again differentiating with respect to t

Next, we set h'=0



Now 
Since at t=1, h''<0.
The function of height has a maximum value.
The maximum of h is = -16.(1)²+32
= -16+32
=16 feet
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀