Original Polynomial

Coefficient Concept Expansion

The Power of the term with 1 as the coefficient is 3.
A coefficient is a number multiplied by some variable. For instance, 4x has a coefficient of 4 or 56x has a coefficient of 56.
Answer:
5
Step-by-step explanation:
Refer to attachment for marking of sides.
In the given figure , ∆ABC , ∆ABD and ∆ADC are right angled triangles . Therefore here we can use the Pythagoras theorem , as ,
base² + perpendicular² = hypotenuse ² .
<u>•</u><u> </u><u>In </u><u>∆</u><u>A</u><u>B</u><u>D</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>;</u>
AB² + BD² = AD²
AB² + x² = 10²
AB² = 10² - x²
AB² = 100 - x²
<u>•</u><u> </u><u>Again</u><u> </u><u>in </u><u>∆</u><u>A</u><u>D</u><u>C</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>;</u>
AC² + AD² = CD²
AC² = 20² - 10²
AC² = 400 - 100
AC² = 300
<u>Again</u><u> </u><u>in </u><u>∆</u><u>A</u><u>B</u><u>C</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>,</u>
AC² = AB² + BC²
Substituting the values from above ,
300 = 100-x² + (20-x)²
300 = 100 - x² + 400 + x² - 40x
40x = 500 - 300
40x = 200
x = 200/40
x = 5
<h3>
Hence the required answer is 5 .</h3>
Answer:
It is pi over nine, the one that your cursor is on. Forgive me if I am wrong
Step-by-step explanation:
Answer: C. 625 and 81
Step-by-step explanation: A relatively prime pair is a pair in which in both numbers given, the only number that can go into each number is one. In 112 and 36, we know 2 can evenly go into each number because they both end in a positive number (112/2 is 56 and 36/2 is 18.) This means A is incorrect. As for B, 11 can evenly go into each number, leaving you with 25 and 7. B is incorrect. And then there's D. 5 can go into each number giving you 160 and 19. D is incorrect.
C is correct because the only numbers that can go evenly into 81 is 1, 3, 9, 27, and 81. None of these numbers, except one can go into 625 also.
Looking at this we can group like terms. What are like terms? They are terms that have the same variable that we can add or subtract. In this case the like terms are 6m and m because they both have the same variable and we could add them together to get 7m.