Answer:

Step-by-step explanation:
Given
--- Initial Amount
every 10 years
Required
The remaining amount after 300 years
To do this, we make use of:

Where
r = decay rate
T = the period of decay
In 300 years, there are 30 periods of 10 years.
i.e.






Answer:
because its not the average
Step-by-step explanation:
it may be in the middle of the graph but its not the average(which would be the center), and if you do the math it would end up making 7 the average
hope this helps
Answer:
1
Step-by-step explanation:
1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.
For this problem,we use the Fundamental Counting Principle. You know that there are 7 digits in a number. In this principle, you have to multiply the possible numbers for every digit. If the first number cannot be zero, then there are 9 possible numbers. So, the value for the first digit is 9. The second digit could be any number but less of 1 because it was used in the 1st digit. So, that would be 10 - 1 = 9. The third digit must be the value in the second digit less than 1. That would be 9 - 1 = 8. And so on and so forth. The solution would be:
9×9×8×7×6×5×4 = 544,320 7-digit numbers
<h3>
System of equations.</h3>

Put (1) to (2):

Substitute the value of x to (1):

Solution:
