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bekas [8.4K]
3 years ago
13

The function f(x) = –x2 – 4x + 5 is shown on the graph.

Mathematics
1 answer:
Masja [62]3 years ago
6 0
I believe it’s The domain of the function is all real numbers less than or equal to -2
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What is the answer to the q's
TEA [102]

Answer:

1.TRUE

2.TRUE

3.FALSE

4.TRUE

4 0
4 years ago
12x5 – 10x2 + x – 45
qaws [65]
(a)
12x  ^{5}    - 10x ^{2}  + x - 45
(b)we have 4 terms in this expression.
(c)+12 is the leading coefficient in
12x ^{5}

(d) constant is -45
6 0
3 years ago
Find the standard form of the equation of the circle with endpoints of a diameter at the points (9,2) and (-7.4).
kicyunya [14]

Answer:

(x-1)²+(y-3)²=65

Step-by-step explanation:

the common view of the equation of a circle is:

a) (x-a)²+(y-b)²=r², where (a;b) - the centre of the required circle, r - the radius of the required circle;

b) using the coordinates of the endpoint of the given diameter it is possible to calculate the coordinates of the centre of the required circle and its radius²:

the coordinate x of the required circle is: (9-7)/2=1;

the coordinate y of the required circle is: (2+4)/2=3.

the radius² of the required circle is:

r²=0.25*[(9- -7)²+(2-4)²]=0.25*260=65.

c) after the substitution the values of 'a'; 'b' and 'r²' into the common equation of the circle:

(x-1)²+(y-3)²=65.

PS. additional: the given points (9;2) and (-7;4) belong to the final equation, if to substitute their coordinates into it.

The suggested way of solution is not the only one.

5 0
3 years ago
Which is the correct calculation of the y-coordinate of point A? 0 (0 - 0)2 + (1 - y2 = 2 O (0 - 1)² + (0- y2 = 22 (0-0)² + (1 -
dimaraw [331]

Answer:

The y-coordinate of point A is \sqrt{3}.  

Step-by-step explanation:

The equation of the circle is represented by the following expression:

(x-h)^{2}+(y-k)^{2} = r^{2} (1)

Where:

x - Independent variable.

y - Dependent variable.

h, k - Coordinates of the center of the circle.

r - Radius of the circle.

If we know that h = 0, k = 0 and r = 2, then the equation of the circle is:

x^{2} + y^{2} = 4 (1b)

Then, we clear y within (1b):

y^{2} = 4 - x^{2}

y = \pm \sqrt{4-x^{2}} (2)

If we know that x = 1, then the y-coordinate of point A is:

y = \sqrt{4-1^{2}}

y = \sqrt{3}

The y-coordinate of point A is \sqrt{3}.  

4 0
3 years ago
​ c(1)=−20 c(n)=c(n−1)+10 ​ Find the 2nd term in the sequence.
Bad White [126]

Answer:

-10 is the second term.

Step-by-step explanation:

After the first term each term is obtained from the previous one by adding 10.

c(1) = -20

so c(2) = -20 + 10

= -10.

3 0
3 years ago
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