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Zigmanuir [339]
3 years ago
10

jill bought a cd for $1000 that earns 4.2% apr and is compounded monthly. The cd matures in 2 years. How much will this cd be wo

rth at maturity?
Mathematics
2 answers:
OLEGan [10]3 years ago
7 0
A = P(1+r/12)^12t, where A = amount after two years, P = Initial amount = $1000, r =apr = 4.2% = 0.042, t = period = 2 years

Then,

A = 1000 (1+0.042/12)^12*2 = $1087.47
LUCKY_DIMON [66]3 years ago
7 0
The value at maturity will be given by compound formula given by:
FV=P(1+r/100*n)^n*t
where:
FV=future value=value at maturity
p=principle
r=rate
n=number of terms
t=time
Thus plugging our values in the formula we get:
P=$1000; r=4.2, t=2 years, n=12 terms
FV=1000(1+4.2/12*100)^2*12
FV=1000(1+0.0035)^24
FV=1087.469396
Thus the value at maturity will be $1087.469396
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How do solve you do 5b/2=27.5
inna [77]
2.5 b = 27.5
b = 27.5 / 2.5

b = 11
6 0
3 years ago
What is a possible solution for x+6≥10
ira [324]

Answer:

4,5,6

Step-by-step explanation:

*The sign of ≥ means that it must be greater or equal to 10 in this case

1). 3 isn't a possible solution due to 9 being less than 10

3+6_10

9_10

9<10

2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10

4+6_10

10_10

10=10

3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10

5+6_10

11_10

11>10

4).6 is a possible solution due to the sum of 6 and 6 being larger than 10

6+6_10

12_10

12>10

Hope this helped! (:

6 0
3 years ago
Prove: segment SD = segment PD
Elza [17]

Answer:

C

Step-by-step explanation:

SD is congruent to PD and both triangles share the same side with each other.

7 0
3 years ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
3 years ago
Please helpp me i need a answer
Lesechka [4]

Answer:

0.0005123

Step-by-step explanation:

The scientific notation 5.123e-4 is same as 5.123×10^-4 or 5.123×10-4. Thus, to get the answer to 5.123e-4 as a decimal, we multiply 5.123 by 10 to the power of -4.

= 5.123e-4

= 5.123 × 10-4

= 0.0005123

7 0
2 years ago
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