Answer: 3
<u>Explanation:</u>
Since we want the least number of integers, divide by the largest integer (9).
2018 ÷ 9 = 224 remainder 2
So, N = 2999...999 <em>(there are 224 of the 9's) </em>
Thus, N + 1 = 2999...999 + 1 <em>(there are 224 of the 9's) </em>
<em> </em>= 3000...000 <em>(there are 224 of the 0's) </em>
The sum of the digits is: 3 + 0 + ... + 0 <em>(there are 224 of the 0's) </em>
= 3
Simplify the following:
k - 2 (k - (2 - k)) - 2
-(2 - k) = k - 2:
k - 2 (k + k - 2) - 2
Grouping like terms, k + k - 2 = (k + k) - 2:
k - 2 ((k + k) - 2) - 2
k + k = 2 k:
k - 2 (2 k - 2) - 2
-2 (2 k - 2) = 4 - 4 k:
k + 4 - 4 k - 2
Grouping like terms, k - 4 k - 2 + 4 = (4 - 2) + (k - 4 k):
(4 - 2) + (k - 4 k)
k - 4 k = -3 k:
-3 k + (4 - 2)
4 - 2 = 2:
Answer: 2 - 3 k
58.50
10%= 4.50
5%= 2.25
6.75*2= 13.50
45+ 13.50= 58.50
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Step-by-step explanation:
Y=kx......5=0.1k....k=5/0.1.....k=50
