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Gwar [14]
3 years ago
10

What is the absolute value of 0.6?

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0
The absolute value of 0.6 is 0.6 beacause its the same thing
Alex_Xolod [135]3 years ago
7 0

Answer:

0.6

Step-by-step explanation:

We are given that  0.6

We have to find the absolute value of 0.6

Absolute value of a number : it is defined as the magnitude of a number .

If a number x

Then, its absolute value is given by

\mid x\mid=x

It is always  positive because it is distance of a number  from zero .

Absolute value of 0.6 is given by

\mid 0.6\mid=0.6

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Pls Help!!! Worth 99 Pts!!
Alenkasestr [34]
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)

To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0   x=-4   x=2

So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)

And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5 
3 gets us 21

So now you know end behavior, zeroes, and signs of intervals

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6 0
3 years ago
Read 2 more answers
What expression is equivalent to (10x)^-3
irakobra [83]

Answer:

1/ (1000x^3)

Step-by-step explanation:

yes

6 0
3 years ago
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10/2x5 using order of operations
Jlenok [28]

Answer:

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Step-by-step explanation:

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7 0
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5 0
3 years ago
Csc\theta -cot\theta =\frac{sin}{1+cos\theta }
Inga [223]

Answer:

Step-by-step explanation:

Left Hand Side

Change to sin(theta) and cos(theta)

csc(theta) = 1/sin(theta)

cot(theta) = cos(theta)/sin(theta)

1/sin(theta) - cos(theta)/sin(theta)                   Put over Sin(theta) Common denominator

[1 - cos(theta)] / sin(theta)                                Multiply numerator and denominator by 1 + cos(theta)

(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))

(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)

sin^2(theta) / (sin(theta)* ( 1 + cos(theta)

sin(theta) / (1 + cos(theta) )

Right hand Side.

See Above.

4 0
3 years ago
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