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neonofarm [45]
3 years ago
6

30 POINTS! Find the rms value of the function i = 15(1 - e1/zt) from t = 0 to t = 4.

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0
Hello,
Please, see the attached file.
Thanks.

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Make t the subject of the formula in D=k/f(b+t)
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Answer:

(k/Df)-b = t

t=(k/Df)-b

Step-by-step explanation:

D = k/f(b+t)

k/D = f(b+t)

k/Df = b+t

(k/Df)-b = t

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Slove the following:​
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Answer:

let required no be x

\frac{1}{7}  =  \frac{x}{42}

by doing crisscrossed multiplication

42 \times 1 = 7 \times x

42=7x

dividing both side by 7

\frac{42}{7}  = 7x \div 7

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I NEED HELP!! ASAP!! 3x + -7 = 42
Dmitrij [34]

Answer:

16 1/3

Step-by-step explanation:

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3 years ago
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Should be the blue marble
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2 years ago
P is inversely proportional to the cube of (q-2) p=6 when q=3 find the value of p when q is 5
sveticcg [70]
\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{  k}}}{x}
\end{array}\\\\
-----------------------------\\\\
\textit{p is inversely proportional to the cube of (q-2)}\implies p=\cfrac{k}{(q-2)^3}
\\\\\\
now \quad 
\begin{cases}
p=6\\
q=3
\end{cases}\implies 6=\cfrac{k}{(3-2)^3}

solve for "k", to find k or the "constant of variation"

then plug k's value back to \bf p=\cfrac{k}{(q-2)^3}

now.... what is "p" when q = 5?  well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is
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