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3 years ago

Which expression is equivalent to 3x^-6y^-3/15x^2y^10 ? Assume x=0 and y=0

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{3x^{-6}y^{-3}}{15x^2y^{10}}\implies \cfrac{3}{15}\cdot \cfrac{x^{-6}y^{-3}}{x^2y^{10}}\implies \cfrac{1}{5}\cdot \cfrac{1}{x^2x^6y^{10}y^3}
\\\\\\
\cfrac{1}{5}\cdot \cfrac{1}{x^{2+6}y^{10+3}}\implies \cfrac{1}{5x^8y^{13}}$

Anit [1.1K]3 years ago

7 0

Find the attachment below

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Select the expressions that are equivalent to 7(7w).

Jet001 [13]

Answer:

answers are A and C

Step-by-step explanation:

they both will equal 49w

Please Brainliest will be much appreciated

3 0

2 years ago

You have one type of candy that sells for $1.70/lb and another type of candy that sells for $3.40/lb. You would like to have 8.5

Andrew [12]

Answer: You will need 3.5lbs of the cheaper candy

and 5 lbs of the expensive candy.

Step-by-step explanation:

Let x represent the number of pounds of the cheaper candy that you would need.

Let y represent the number of pounds of the expensive candy that you would need.

You would like to have 8.5 lbs of a candy mixture. It means that

x + y = 8.5

You have one type of candy that sells for $1.70/lb and another type of candy that sells for $3.40/lb. The candy mixture would sell for $2.70/lb. It means that the total cost of the mixture would be 8.5 × 2.7 = $22.95. The expression would be

1.7x + 3.4y = 22.95- - - - - - - - - - - 1

Substituting x = 8.5 - y into equation 1, it becomes

1.7(8.5 - y) + 3.4y = 22.95

14.45 - 1.7y + 3.4y = 22.95

- 1.7y + 3.4y = 22.95 - 14.45

1.7y = 8.5

y = 8.5/1.7

y = 5

x = 8.5 - y = 8.5 - 5

x = 3.5

5 0

2 years ago

-18 = 8 x <br>x=? please give explanation

Kisachek [45]

You would divide by 8 on each side

-2.25 = x

6 0

3 years ago

How do I solve for x? I tried using law of sines and law of cosines but the angles and sides don't match up.

valentina_108 [34]

Law cosines: $y^{2} =$ 16 + 256 - 128 $\sqrt{3} ;$ => y ≈ 16.51;
Law sines: 16/sinx = 16.51/sin30 => sinx = 0.48 => x ≈ 29 degrees;

8 0

3 years ago

Please help id appreciate it and please give me full answers. I will report.

stepan [7]

Answer:

Part 1. 28 miles

Part 2. 16^2 + 12^2 = c^2

Part 3. 8 miles. All work is in step by step explanation.

Part 4. 8 miles

Step-by-step explanation:

Part 1. The total distance that Jane travels biking and running is 28 miles. This is because we add 16 and 12 which is her total route.

Part 2. The Pythagorean theorem is a^2 + b^2 = c ^2. In this case, the variable a is Jane's bike route(16 miles), the variable b is Jane's running route(12 miles), and the variable c is the Trainer's biking route as given. If we replace all variables with the values in miles, the equation would be 16^2 + 12^2 = c^2.

Part 3. WORK USED FROM EQUATION

16^2 = 16*16 = 256

12^2 = 12*12 = 144

Now we replace the numbers with the exponents with the solved numbers.

256 + 144 = c^2

256 + 144 = 400

400 = c^2

c = sqrt400

c = 20

Finally, we take the value of c and subtract it from the total distance of Jane's route which is 28 miles(as explained above).

28 - 20 = 8.

Hence, the answer is 8 miles

8 0

2 years ago