Question

What is the factored form of this expression? 27m^3 +125n^3

Answer 1

Answer:

$\left(3m+5n\right)\left(9m^2-15mn+25n^2\right)$

Step-by-step explanation:

$27m^3+125n^3=\left(3m\right)^3+\left(5n\right)^3$

Apply sum of cubes formula: $x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)$

$\left(3m\right)^3+\left(5n\right)^3=\left(3m+5n\right)\left(3^2m^2-3m\times 5n+5^2n^2\right)$

$\left(3m+5n\right)\left(9m^2-15mn+25n^2\right)$

Answer 2

(3m+5n)(9m^2 - 15mn+25n^2)