The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
Let me see some q,,,,,,,,,,,,,,,
Dafna11 [192]
Step-by-step explanation:
huh??????????????????
For the proof here kindly check the attachment.
We are given that
. Also, the transversal is shown. Let us take the first case, that of
and
. Please note that all other proofs will follow in a similar manner.
Let us begin, please have a nice look at the diagram. We will see that
and
are vertically opposite angles. We know that vertically opposite angles are congruent. Thus,
and
are congruent angles.
=
Now, we know that
and
are alternate interior angles. We also, know that alternate interior angles are equal too. Thus, we have:
= 
From the above arguments it is clear that:
=
=
.
Thus,
= 
We have proven the first instance. Please note that all other instances can be proved in a similar fashion.
For example, for
and
we can take
and
as vertically opposite angles thus making
=
. Now,
and
are alternate interior angles and thus
and
are equal. Thus, we have
and
.
It is the areas of a road that can not be seen by the driver when looking forward or through the side mirrors or rear-view.
-Mabel <3
(If you don't mind, please give brainliest )
No
If two planes intersect each other, the intersection will always be a line. where r 0 r_0 r0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.