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jeka57 [31]
3 years ago
15

Harold uses a cone shaped feeder, with a diameter of 7.5 centimeters and a height of 3.5 centimeters, to feed his tropical fish.

How many cubic centimeters of feed can this feeder hold? Use 3.14 for pi. Enter your answer in the box as a decimal rounded to the nearest tenth.
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
4 0
To find the volume of a cone you use the formula "1/3 x 3.14 x r^2 x h". Plug the formula into the problem. 1/3 x 3.14 x 3.75^2 x 3.5 =51.51. Rounded to the nearest tenth is 51.5. Hope this helps! 
MissTica3 years ago
4 0

Answer: 51.5\ cm^3

Step-by-step explanation:

We know that the volume of a cone is given by :-

\text{Volume}=\frac{1}{3}\pi r^2h, where r is the radius and h is the height of the cone.

Given: Diameter of cone = 7.5 centimeters

Therefore, radius = \frac{7.5}{2}=3.75\text{ cm}

Height of cone = 3.5 cm

Thus, the volume of given cone will be :-

\text{Volume}=\frac{1}{3}(3.14)(3.75)^2(3.5)\\\\\Rightarrow\text{Volume}=51.515625\approx51.5\ cm^3

Hence, the given feeder can hold  51.5\ cm^3  of feed .

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An expression is shown below. Which expression is equivalent to the expression shown?
Vera_Pavlovna [14]

Note: In option A, it should be "+" instead of "(".

Given:

The expression is

-2x(x+y-3)+3(-x+4y)+y(3x+5y-3)

To find:

The equivalent expression.

Solution:

We have,

-2x(x+y-3)+3(-x+4y)+y(3x+5y-3)

Using distributive property, we get

=-2x(x)-2x(y)-2x(-3)+3(-x)+3(4y)+y(3x)+y(5y)+y(-3)

=-2x^2-2xy+6x-3x+12y+3xy+5y^2-3y

On combining like terms, we get

=-2x^2+5y^2+(-2xy+3xy)+(6x-3x)+(12y-3y)

=-2x^2+5y^2+xy+3x+9y

The expression -2x^2+5y^2+xy+3x+9y is equivalent to the given expression.

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6 0
3 years ago
1 3/4 TIMES 1/2 = ??? <br> PLS HELP FR NOW!!
Orlov [11]
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3 0
2 years ago
Read 2 more answers
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
2 years ago
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