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Sonbull [250]
3 years ago
14

[c++] Write a recursive function takes a word string as input argument and reverse the word. Print out the results of recursive

calls. Also write a main program accepts input from the user and then call the recursive function.
Example:
Enter a word: hello
h
eh
leh
lleh
olleh ...?
Computers and Technology
1 answer:
Aleks04 [339]3 years ago
3 0
I will try to give you the best answer I can possibly come up with. 
The easy way to get it is to store it into an array of strings and print the array of string backwards. You can do that by starting at the last part of the array down to the first letter.
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Which of the following is true about advertisements?
katrin [286]

the answer is they often contain biases :)

3 0
2 years ago
If it is impractical to place guest users in a secure network, isolated from the production network by firewall barriers, then:
IgorLugansk [536]

Answer:

specific areas of access should be determined and they should be as restrictive as possible.

Explanation:

According to my research on security features of networks , I can say that based on the information provided within the question then specific areas of access should be determined and they should be as restrictive as possible. This would provide the highest level of security while still allowing production to be smooth.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

7 0
3 years ago
Develop a CPP program to test is an array conforms heap ordered binary tree. This program read data from cin (console) and gives
mafiozo [28]

Answer:

Following are the code to this question:

#include<iostream>//import header file

using namespace std;

int main()//defining main method

{

int ar[7];//defining 1_D array that stores value      

int i,x=0,l1=1,j; //defining integer variable

for(i=0;i<7;i++)//defining for loop for input value from user ends  

{

cout<<"Enter a Number: ";//print message

cin>>ar[i];//input value in array

if(l1<=2 && i>0)//using if block that checks the array values  

{

x++;//increment the value of x by 1  

}

if(l1>2 && i>0)//using if block that checks the array values  

{

l1=l1-2;//using l1 variable that decrases the l1 value by 2  

}

j=i-x;//using j variable that holds the index of the root of the subtree

if(i>0 && ar[j]>ar[i])// use if block that checks heap condition  

{

l1++; //increment the value of l1 variable

}

if(i>0 && ar[j]<ar[i])// using the if block that violate the heap rule  

{

cout<<ar[i]<<" "<<"Violate the heap";//print message with value

break;//using break keyword  

}

}

return 0;

}

Output:

1)

Enter a Number: -15

Enter a Number: -5

-5 Violate the heap

2)

Enter a Number: 45

Enter a Number: 0

Enter a Number: 55

55 Violate the heap

Explanation:

  • In the above-given C++ language code, an array "ar" and other integer variables " i,x,l1, j" is declared, in which "i" variable used in the loop for input values from the user end.
  • In this loop two, if block is defined, that checks the array values and in the first, if the block it will increment the value of x, and in the second if the block, it will decrease the l1 value by 2.
  • In the next step, j variable is used that is the index of the root of the subtree. In the next step, another if block is used, that checks heap condition, that increment the value of l1 variable. In the, if block it violate the heap rule and print its values.
5 0
3 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
Which camera does Angelina use?
julia-pushkina [17]

Answer:

mirrorless cameras have lot more space due to not having mirrors. and they have the same or better quality than DSLR's.

8 0
3 years ago
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