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3 years ago

In ∆ABC, the median AM (M ∈ BC ) is perpendicular to the angle bisector BK (K ∈ AC ). Find AB, if BC = 12 in. Show with work

Mathematics

1 answer:

otez555 [7]3 years ago

3 0

Call the point where BK intersects AM point X. BX is the altitude of ∆ABM, and it is also the angle bisector of angle ∠ABM. Hence ∆ABM is isosceles, and AB ≅ MB.

M is the midpoint of BC, which is 12 inches long. Hence MB is half that length, or 6 inches.

Since AB is the same length as MB, which is 6 inches, ...

... AB is 6 inches.

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Which product is positive?

Natalija [7]

Option D:

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Solution:

If the negative sign is in even number of times then the product is positive.

If the negative sign is in odd number of times then the product is negative.

To find which product is positive:

Option A:

$$\left(\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option B:

$$\left(-\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option C:

$$\left(\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative sign = 1

1 is an odd number.

So, the product is negative.

Option D:

$$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$

Here, number of negative sign = 2

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So, the product is positive.

Hence option D is the correct answer.

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Ne4ueva [31]

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mihalych1998 [28]

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lakkis [162]

Answer:

Step-by-step explanation:

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3 years ago

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Blababa [14]

Answer:

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Step-by-step explanation:

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Inverse operation of division: multiplication

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