In ∆ABC, the median AM (M ∈ BC ) is perpendicular to the angle bisector BK (K ∈ AC ). Find AB, if BC = 12 in. Show with work
1 answer:
Call the point where BK intersects AM point X. BX is the altitude of ∆ABM, and it is also the angle bisector of angle ∠ABM. Hence ∆ABM is isosceles, and AB ≅ MB.
M is the midpoint of BC, which is 12 inches long. Hence MB is half that length, or 6 inches.
Since AB is the same length as MB, which is 6 inches, ...
... AB is 6 inches.
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Answer:
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Step-by-step explanation:
The Pythagorean Theorem states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides. This only works on right triangles. The equation for this is . A and B are the shorter side lengths, while C is the hypotenuse. Taking the squares of the two shorter sides will equal the square of the hypotenuse.
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