I'll give brainiest , 5 stares help

2x + 5 =12 What is x

lisabon 2012 [21]

Answer:

7/2

Step-by-step explanation:

2x=12-5....collectible like terms

2x=7

x=7/2...dividing both side by 2

3 0

2 years ago

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What is the value of x to the nearest tenth?

Colt1911 [192]

Answer:

C. 17.6

General Formulas and Concepts:

Math

Rounding

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

Step 1: Identify Variables

Angle θ = 40°

Opposite Leg = x

Adjacent Leg = 21

Step 2: Solve for x

Substitute in variables [tangent]: $\displaystyle tan(40^\circ) = \frac{x}{21}$
[Multiplication Property of Equality] Isolate x: $\displaystyle 21tan(40^\circ) = x$
Rewrite: $\displaystyle x = 21tan(40^\circ)$
Evaluate: $\displaystyle x = 17.6211$
Round: $\displaystyle x \approx 17.6$

6 0

2 years ago

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Create the quadratic function that contains the points (0,2), (1,0), and (3,10). Show all of your work for full credit.

Marina86 [1]

Answer:

y=7/3x²-13/3x+2

Step-by-step explanation:

Determine the value of c:

y=ax²+bx+c

2=a(0)²+b(0)+c

2=c

Substitute (1,0) into the quadratic and create an equation with a and b:

y=ax²+bx+2

0=a(1)²+b(1)+2

0=a+b+2

-2=a+b

Do the same with (3,10) to get a second equation:

y=ax²+bx+2

10=a(3)²+b(3)+2

10=9a+3b+2

8=9a+3b

Set the two equations equal to each other and solve for a and b:

-2=a+b

8=9a+3b

Multiply first equation by 3 and eliminate b to find a:

-6=3a+3b

- (8=9a+3b)

_______

-14=-6a

14/6=a

7/3=a

Substitute 7/3=a into the first equation:

-2=7/3+b

-2-(7/3)=b

-13/3=b

Final equation:

y=7/3x²-13/3x+2

See the graph for a visual representation

7 0

2 years ago

Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.

valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to $d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}$