Ask question

Ask question

All categories

3 years ago

6

Or her comic books and then bought 8 more. She now has 13. How many did she begin with?

1 answer:

OLga [1]3 years ago

3 0

13-8= 5 comic books to begin with,
is that the problem?

You might be interested in

Without solving it, determine the nature of the roots of this equation:

ycow [4]

<h2>Answer:</h2>

x = 1, -4

Step-by-step explanation:

Find the roots of x:

2 + 3

x − 4 = 0 by solving for x

.

6 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

4 years ago

Given g(x) = 10x + 2, find x when g(x) = 2.

Elan Coil [88]

Answer:

x=0

Step-by-step explanation:

We are given:

g(x) =10x +2

and

g(x)=2

g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other

10x+2=2

Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides

10x+2-2=2-2

10x=0

To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.

10x/10=0/10

x=0

8 0

3 years ago

Which of the following is the best estimate of the circumference of a circle that has a diameter of 7 feet? 42 ft 21 ft 14 ft 11

11Alexandr11 [23.1K]

Answer:

21 ft

Step-by-step explanation:

Hope it helps

3 0

2 years ago

Read 2 more answers

What were the dimensions of the slice defined as RSTU in Exercise 1?

antoniya [11.8K]

Answer:

how can I tell u the answer which out a pic

Step-by-step explanation:

7 0

3 years ago